Question

In a certain skyscraper, the elevator whisk you a restaurant in the skyscraper at a speed of 500 feet in 60 seconds. If the restaurant is 300 feet up, how long will it take you to reach the restaurant by elevator?

Answer 1

`\bf \begin{array}{ccll} feet&seconds\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 500&60\\ 300&x \end{array}\implies \cfrac{500}{300}=\cfrac{60}{x}\implies \cfrac{5}{3}=\cfrac{60}{x}\implies x=\cfrac{3\cdot 60}{5}`

Answer 2

The elevator will take you up at 300 feet in 36 seconds.

Explanation:

Let the time taken to go up 300 feet be = t seconds

Given is that the elevator takes you up at 500 feet in 60 seconds.

So, we can derive a relation as:

`(500)/(60)= (300)/(t)`

=>
`500t=300*60`

=>
`500t=18000`

t = 36 seconds

So, the elevator will take you up at 300 feet in 36 seconds.