176,451 views
20 votes
20 votes
PLEASE HELP

I just need help with this one question, im having trouble with it. Find an equation of the line that is perpendicular to the line shown below and passes through the point (-4,5). Show your work. ​

PLEASE HELP I just need help with this one question, im having trouble with it. Find-example-1
User Arpit Khandelwal
by
2.8k points

1 Answer

10 votes
10 votes

Answer:


y=(-1)/(2)x +3

Explanation:

Take any two points from the graph

(2 , 0) ; (0 , -4)

Slope =
(-4-0)/(0-2)\\\\


= (-4)/(-2)\\\\= 2

Slope of the perpendicular line = -1/m = -1/2 = -1/2

m = -1/2 ; (-4 , 5)

y - y1 = m(x - x1)


y - 5 = (-1)/(2)(x -[-4] )\\\\y - 5= (-1)/(2)(x + 4)\\\\y - 5 = (-1)/(2)x +(-1)/(2)*4\\\\y-5 = (-1)/(2)x -2\\\\y = (-1)/(2)x-2+5\\\\y=(-1)/(2)x + 3

User Mikel San Vicente
by
3.5k points