Question

Find the center of the circle whose equation is x² + y² = 4.

Answer 1

Since the center of the circle is represented by whatever numbers are being subtracted by x and y, and there are no numbers tagged to x and y, your center is the origin, or (0,0).

Answer 2

The center of circle is
`(0,0)`

Explanation:

We need to find the center of the circle of the equation
`x^(2)+y^(2)=4`

Since, the general equation of circle is
`(x-h)^(2)+(y-k)^(2) = r^(2)`

Where (h,k) is center of circle and r is radius.

Re-write the circle equation is
`x^(2)+y^(2)=4` as,

`x^(2)+y^(2)=2^(2)`

Compare
`x^(2)+y^(2)=2^(2)` with
`(x-h)^(2)+(y-k)^(2) = r^(2)`

so,
`(x-0)^(2)+(y-0)^(2) = 2^(2)`

Hence, the center of circle is
`(0,0)`