47.4k views
4 votes
A hair dryer draws 14.5 a when plugged into a 120-v line. assume direct current.

User Kpeatt
by
5.5k points

1 Answer

4 votes
Missing part in the exercise. Complete text:
"A hair dryer draws 14.5 A when plugged into a 120-V line. Assume direct current.

(a) What is its resistance? Express your answer to two significant figures and include the appropriate units."

(b) How much charge passes through it in 11 min ? Express your answer to two significant figures and include the appropriate units.


Solution

(a) We can calculate the resistance by using Ohm's law:


\Delta V= I R

Since we know that
\Delta V=120 V and
I=14.5 A, we can find R:


R= (\Delta V)/(I) = (120 V)/(14.5 A)=8.3 \Omega


(b) The current is equal to the quantity of charge by unit of time:


I= (Q)/(t)

In our problem, t=11min=660 s, so we can calculate the charge passed through the hair dryer:


Q=It=14.5 A \cdot 660 s = 9570 C

User Eric MSFT
by
5.7k points