Missing part in the exercise. Complete text:
"A hair dryer draws 14.5 A when plugged into a 120-V line. Assume direct current.
(a) What is its resistance? Express your answer to two significant figures and include the appropriate units."
(b) How much charge passes through it in 11 min ? Express your answer to two significant figures and include the appropriate units.
Solution
(a) We can calculate the resistance by using Ohm's law:

Since we know that
and
, we can find R:

(b) The current is equal to the quantity of charge by unit of time:

In our problem, t=11min=660 s, so we can calculate the charge passed through the hair dryer:
