Question

1: Evaluate x•y+9•X-3 when x=7 and y=10

2: Evaluate 140=(x+9)+(x+4)2 when x=1

(show steps)​

Answer 1

See below.

Explanation:

1. x•y+9•X-3 when x=7 and y=10

(7)•(10)+9•(7)-3

70 + 63 - 3

70 + 60

= 130

2: Evaluate 140=(x+9)+(x+4)2 when x=1

140=(x+9)+(x+4)2

140 = (1 + 9) + (1 + 4)2

140 = 10 + 10 = 20 Not true. There must be something incorrect with the question.

Is the (x+4)2 supposed to be (x+4)^2?

140 = (1 + 9) + (1 + 4)^2 ?

Still not true.

Is the question to find the value of X?