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Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?

A). Y=-4x^5+12x^4-6x and y=5x^3-2x
B). Y=4x^5-12x^4+5x^3+4x and y=0
C). Y=4x^5-12x^4+6x and y= -5x^3+2x
D). Y=4x^5-12x^4+6x and y=5x^3-2x

User Imladris
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2 Answers

4 votes
D is the answer......................
User Ward Bekker
by
8.4k points
3 votes

Answer:

D). Y'=
4x^(5)-12x^(4)+6x and y'=
5x^(3)-2x

Explanation:

We are given the equation
4x^(5)-12x^(4)+6x=5x^(3)-2x.

On simplifying this equation, we get
4x^(5)-12x^(4)-5x^(3)+8x=0

i.e. Let, Y'=
4x^(5)-12x^(4)+6x and y'=
5x^(3)-2x

Now, according to the options,

A) Y =
-4x^(5)+12x^(4)-6x = -Y' , that means the graph will be inverse of the required graph.

B) As the coefficient of 'x' in our given equation and the equation of option B are different, both will have different graphs.

C) As y =
-5x^(3)+2x = -y', this means that the graph will be inverse of the required graph.

Hence, all above options are discarded and so option D is correct.

User Paul Hannon
by
7.6k points

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