Question

1.)Based on the average.how many people will usethe ramp each week? Setup ratio.2.) What will the surface areaof the ramp be? Writeequation & solve. Roundto the nearest hundredth.3.) What percentage of thepeople do not need theramp?4.) How high will the ramp be9 feet from the front walk?Draw a diagram & solve.5.) How high will the ramp be6 feet fromthe front walk?Draw a diagram & solve.Please help with these questions.thank you.

Answer 1

1)

Let:

N = Total people every week = 207

r = People which needs a ramp = 1:9 = 1/9

So:

`N\cdot r=207\cdot(1)/(9)=23`

Answer: 23 people

2)

`\begin{gathered} SA=b\cdot h+pw \\ _{\text{ }}where\colon \\ b=18ft \\ h=4ft \\ p=b+h+l \\ l=\sqrt[]{h^2+b^2} \\ l=\sqrt[]{340} \\ w=4.75ft \end{gathered}`

Therefore:

`\begin{gathered} SA=72+192.09 \\ SA=264.09ft^2 \end{gathered}`

3)

The percentage of the people that don't need the ramp will be given by:

`1-r=1-(1)/(9)=(8)/(9)\approx0.89`

Answer: Approximately 89%

4)

`\begin{gathered} h=\sqrt[]{(\sqrt[]{340})^2-9^2} \\ h=\sqrt[]{259} \\ h\approx16.09ft \end{gathered}`

5)

`\begin{gathered} h=\sqrt[]{(\sqrt[]{340})^2-6^2} \\ h=\sqrt[]{340} \\ h\approx17.44ft \end{gathered}`