Question

player A led a baseball league in runs batted in for the 2006 regular season. player B. who came in second player to A, had 13 fewer runs batted in for the 2006 regular season. together, these two players brought home 250 runs during the regular 2006 regular season. how many runs batted in did the player A and B each account for?

Answer 1

a= player A runs batted in
b= player B runs batted in= a-13

250= a + b
substitute b= a-13 for b

250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a

Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b

Hope this helps! :)