Question

Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

Answer 1

5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)


I hope it helps

Answer 2

`(5x-4)(x^2+4)`

Explanation:

Consider the given expression

`5x^3-4x^2+20x-16`

We need to find the factor form of given expression.

Using grouping method we get

`(5x^3-4x^2)+(20x-16)`

Taking out highest common factors from each group.

`x^2(5x-4)+4(5x-4)`

Taking out common factors.

`(5x-4)(x^2+4)`

Therefore, the factored form of given expression is
`(5x-4)(x^2+4)`.