Hello!!
So what they are giving you is the x,y coordinate of the terminal side of an angle. Meaning 4,10 is the point x=4 and y= 10.
So if we have that, then we can solve for the quadrant that the angle falls in. So for two positive values it tells us it falls in quad 1.
So we have x and y so now use x^2+y^2=h^2 to solve for hypotenuse.
So we get h=sqrt(4^2+10^2)= sqrt(116) or 2*sqrt(29).
Now knowing our trig identities.
Sin= y/h
Cos=x/h
Tan=y/x
Csc=h/y=1/sin
Sec=h/x=1/cos
Cot=x/y=1/tan
So now we have
X=4 Y=10 H=2*sqrt(29)
Now we just use the above identities and plug and chug for your answers. Doing the same one point(4,10)
Sin=10/2*sqrt(29)= (5*sqrt(29))/29
Cos=4/2*sqrt(29)= (2*sqrt(29))/29
Tan=10/4=5/2
Sec=2*sqrt(29)/10= sqrt(29)/5
Csc=2*sqrt(29)/4= 2*sqrt(29)/2
Cot=4/10= 2/5
Now do the same thing as above for all sets of your questions.
Hope this helps!! Any questions please just ask! Thank you so much!