Given:
The nth term of a number sequence is
.
To find:
The first 3 terms and the 10th term.
Solution:
We have, nth term of a number sequence.
![a_n=n^2+2n](https://img.qammunity.org/2022/formulas/mathematics/high-school/932f29j12njohdnhf5ueuxn4dpdb6mltej.png)
For n=1,
![a_1=(1)^2+2(1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pmefmlcfliqpwx4j8pcg3oiqhjoye682i5.png)
![a_1=1+2](https://img.qammunity.org/2022/formulas/mathematics/high-school/mmhjokv4qd0u6i7fj1yntqjnwa9sxhbejv.png)
![a_1=3](https://img.qammunity.org/2022/formulas/mathematics/high-school/buzhldf1894b6acauj07zknml6rugxqwg2.png)
For n=2,
![a_2=(2)^2+2(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/o3vo1krce6wyiodk8z5myckrx7l3jdehov.png)
![a_2=4+4](https://img.qammunity.org/2022/formulas/mathematics/high-school/ovy0okkfi4ihelmq4n051eqnv83qs7f1w7.png)
![a_2=8](https://img.qammunity.org/2022/formulas/mathematics/high-school/1r0i3kl8luu0zk1u6x02ehrm90ctv6ac9x.png)
For n=3,
![a_3=(3)^2+2(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/i3h32vsptw88uxi6gw8y5kn22vijiku149.png)
![a_3=9+6](https://img.qammunity.org/2022/formulas/mathematics/high-school/ci7kutijsye4ig0cig90r1uec16gdn907l.png)
![a_3=15](https://img.qammunity.org/2022/formulas/mathematics/high-school/pparavrnhwls1ykgrupz2auzm5opvkl2ro.png)
For n=10,
![a_(10)=(10)^2+2(10)](https://img.qammunity.org/2022/formulas/mathematics/high-school/h1qblspgfiqjqhqgghw23g03sekt6osuhs.png)
![a_(10)=100+20](https://img.qammunity.org/2022/formulas/mathematics/high-school/e3del9y0z3d5l6pywvjz0c4ciuhfqh687w.png)
![a_(10)=120](https://img.qammunity.org/2022/formulas/mathematics/high-school/l3k9e14ru47yxnorbqsc5eip79tu25xecz.png)
Therefore, the first three terms are 3, 8 and 15 respectively. The 10th term is 120.