Question

A ball droped from a building. How fast is it traveling after falling 3.55s

Answer 1

d = 61.75 m

Step-by-step explanation:

Given that,

A ball droped from a building.

We need to find how fast is it traveling after falling 3.55 s.

As it is dropped, its initial velocity is equal to 0.

Let d is the distance it covers after falling 3.55 s.

We can use second equation of motion to find d.

`d=ut+(1)/(2)at^2`

Here, u = 0 and a =g

`d=(1)/(2)gt^2\\\\d=(1)/(2)* 9.8* (3.55)^2\\\\d=61.75\ m`

So, it will cover 61.75 m after falling 3.55 seconds.