Question

ANSWER ASAPPPPPP

Find the length and width of a rectangle with an area of 2x2 + x - 3.

A) l = 2x + 3; w = x + 1
B) l = 2x + 3; w = x - 1
C) l = 3x + 2; w = x - 1

Answer 1

Option B is correct

`length (l) = 2x+3` ;
`width (w) = (x-1)`

Explanation:

Given an area of rectangle in the form of equation:

Area of Rectangle =
`2x^2+x-3`

Formula for the Area of Rectangle: To find the Area of Rectangle in square unit, we multiply the length by width, i.e,

Area of Rectangle (A) =
`length(l) * width(w)`

Factorize the quadratic equation:

`2x^2+x-3`

⇒
`(2x+3)( x-1)`

Since, Area of rectangle =
`2x^2+x-3 = (2x+3) * (x-1)`

or

`l * w= (2x+3) * (x-1)`

then, either
`l` = (2x+3) ,
`w` = (x-1) or
`l = (x-1)` ,
`w`= (2x+3)

The only options we have;
`length (l)` = (2x+3) and width (w) = (x-1)

Answer 2

The leading coefficient of one of the factors will be 2; the product of the constants in the factors will be -3. The only choice matching both these requirements is
.. selection B.