Answer:
The correct answer is option B.
Step-by-step explanation:
Velocity of the walkway =
![v_w=0.9 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/qkcbtdn6bybhupqzyz524habsbvjh4xlg2.png)
velocity of the man =
![v_m=1.1m/s](https://img.qammunity.org/2019/formulas/physics/high-school/tlcb1rozt6a7378qd0uslkdnb9jrlmce3p.png)
Relative velocity of the man with respect to moving walkway =
![v_r](https://img.qammunity.org/2019/formulas/physics/high-school/8208jgevt1g5ocozwa4f1v3sikj3umrbqq.png)
![v_r=v_m-v_w=1.1 m/s-0.9 m/s=0.2 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/ivvght1zmddiv9r0vmpguvaa1dmhkssub4.png)
The relative speed of man with respect to the velocity of walkway is 0.2 m/s towards east direction.