Question

When 135 grams of titanium tetrachloride react with an excess of water, as shown in the unbalanced chemical equation below, how many grams of hydrochloric acid will be produced? Please show all your work for the calculations for full credit.

TiCl4 + H2O yields TiO2 + HCl

Answer 1

Answer: 103.9082 grams of HCl will be produced by 135 grams of titanium tetra chloride.

Step-by-step explanation:

`TiCl_4+2H_2O\rightarrow TiO_2+4HCl`

`moles=\frac{\text{Mass of the compound}}{\text{MOlar mass of the compound}}`

Number of moles of
`TiCl_4=\frac{\text{given mass of the}TiCl_4}{\text{Molar mass of}TiCl_4}=(135 g)/(189.67 g/mol)=0.7117 mol`

According to reaction, 1 mole
`TiCl_4` produces 4 moles of HCl , then 0.7117 moles of
`TiCl_4` will produce :
`(4)/(1)* 0.7117 moles` of HCl that is 2.8468 moles.

Mass of HCl =
`\text{moles of HCl}* \text{Molar mass of HCl}=2.8468 mol* 36.5 g/mol=103.9082 g`

103.9082 grams of HCl will be produced by 135 grams of titanium tetra chloride.

Answer 2

108g. Balance the equation: TiCl4+2H2O yields TiO2+4HCL. The atomic mass of TiCl4=22+17*4=90. Therefore, there are 135/90=1.5 mole of titanium tetrachloride in reactants. Since the coefficient of HCl in products is 4, there are 4*1.5=6 mole of HCl. Its mass is 6*(1+17)=108 grams.