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20 votes
The marking off table has a mass of 500kg.

The regulator has a maximum pressure of 3.5
Bar.
What internal diameter cylinder is required to
lift the table?

User JamesB
by
4.0k points

1 Answer

9 votes

Answer:

0.1336

Step-by-step explanation:

The formula for pressure is force exerted by the object divided by area the object covers.

The marking off table has a mass of 500 kg. You can find its weight by applying the equation;

w= m* g where w is weight , m is mass and g is acceleration due to gravity

w= 500 * 9.81

w= 4905 N

Formula for pressure is;

P= F/A

3.5 *100000 N = 4905 / A

350000 N = 4905 /A

A= 4905/350000

A= 0.0140 m²

To get the internal diameter apply the formula;

A=πr² where A is area of a cylindrical shaped object, r is radius

0.0140 = π * r²

0.0140/π = r²

0.0044608 = r²

√0.0044608 = r

0.06678 m = r ------D = 2r

0.1336 = D

User Colin Williams
by
4.5k points