Question

An Alaskan rescue plane traveling 43 m/s drops a package of emergency rations from a height of 108 m to a stranded party of explorers. The acceleration of gravity is 9.8 m/s^2. Where does the package strike the ground relative to the point directly below where it was released? What is the horizontal component of the velocity just before it hits? What is the vertical component of the velocity just before it hits? (Choose upward as the positive vertical direction)

Answer 1

Step-by-step explanation:

Given:

V₀ = 43 m/s

H = 108 m

g = 9.8 m/c²

____________

L - ?

Vₓ - ?

Vy - ?

1)

Fall time:

H = g*t² / 2

t = √ ( 2*H / g) = √ (2*108 / 9.8) ≈ 4.7 s

L = V*t = 43*4.7 ≈ 200 m

2)

Vx = V₀ = 43 m/s

Vy = - g*t = - 9.8*4.7 ≈ - 46 m/s