Question

2Sr(s)+O2(g)→2SrO(s)

calculate how many grams of the product form when 16.4 of Sr completely reacts.

Assume that there is more than enough of the other reactant.

Answer 1

Mass = 19.68 g

Step-by-step explanation:

Given data:

Mass of product formed = ?

Mass of Sr 16.4 g

Solution:

Chemical equation:

2Sr + O₂ → 2SrO

Number of moles of Sr:

Number of moles = mass /molar mass

Number of moles = 16.4 g/ 87.62 g/mol

Number of moles = 0.19 mol

Now we will compare the moles of Sr with SrO.

Sr : SrO

2 : 2

0.19 : 0.19

Mass of Sr:

Mass = number of moles × molar mass

Mass = 0.19 mol × 103.62 g/mol

Mass = 19.68 g