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If you have 0.5 L of air in a rigid, sealed container at a pressure of 203 kPA and a temp of 203. You heat the contain to 273 K. What is the final pressure of the air?

151 kPA
102 kPA
273 kPA
310 kPA

1 Answer

6 votes
Volume remains constant: P1 x T2 = P2 x T1. Pressure increases in direct proportion to absolute temperature increase.
203kPa x 273K = P2 x 203K = P2 x 55,419.
P2 = 55,419 / 203 = 273kPa final pressure.
User Mnhmilu
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