Question

A chemist prepares two acid solutions. Solution 1: 3 parts sulfuric acid to 7 parts water. Solution 2: 4 parts sulfuric acid to 9 parts water.

Questions:

A.) Use a ratio table to determine which solution is more acidic.

B.) Use a graph to determine which solution is more acidic.

C.) Which method do you prefer? Explain.

Answer 1

A) Solution 2 is more acidic.
Solution 1= 3:7 = 27:63
Solution 2= 4:9 = 28:63
Sorry I can't present the answers next two parts rn.

Answer 2

A) solution 2 is more acidic than solution 1

B) Graph in attachment

C) Ratio method prefer

Explanation:

A chemist prepares two acid solutions.

Solution 1: 3 parts sulfuric acid to 7 parts water

Ratio of sulphur to water
`=(3)/(7)`

Solution 2: 4 parts sulfuric acid to 9 parts water

Ratio of sulphur to water
`=(4)/(9)`

Part A: Using ratio to find the more acidic

First we make same denominator

Solution 1:
`\Rightarrow (3* 9)/(7* 9)=(27)/(63)`

Solution 2:
`\Rightarrow (4* 7)/(9* 7)=(28)/(63)`

As 28 > 27

Therefore, solution 2 is more acidic than solution 1

Part B: Let y amount of sulfuric acid mix with x amount of water.

Equation of solution 1:
`y=(3)/(7)x`

Equation of solution 2:
`y=(4)/(9)x`

Please find attachment for graph.

Part C: part A method is more prefer to find more acidic. Because it gives actual amount of acidic.