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Find the similarity ratio and the ratio of the perimeters of two regular octagons with areas of 18 in2 and 50 in2.

2 Answers

2 votes

Answer:

Your answer would be

a.

3:5; 3:5

Explanation:


User Bardu
by
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3 votes
By definition we have that the area of a regular octagon is:
A = 4.83L ^ 2
Where, L is the length of the octagon side.
the similarity ratio = the area ratio.
We have then:
similarity ratio = (50) / (18) = 25/9.
the ratio of the perimeters
A1 = 4.83L1 ^ 2
L1 ^ 2 = A1 / 4.83
L2 ^ 2 = A2 / 4.83
L1 ^ 2 / L2 ^ 2 = A1 / A2 = 25/9
L1 / L2 = 5/3
The perimeter is:
P1 = 8L1
P2 = 8L2
P1 / P2 = 8L1 / 8L2 = L1 / L2 = 5/3
answer:
similarity ratio:
25: 9
the ratio of the perimeters:
5: 3
User Safrazik
by
6.6k points