Question

24. The air in a small 250 cm birthday balloon is at a pressure of 760 torr. A boy sits on it at

party to pop it
decreasing the volume tc-220 cm just before it pops. What is the new pressure assuming
constant temperature.

Answer 1

1.14atm

Step-by-step explanation:

Given parameters:

V1 = 250cm³ ;

1000cm³ = 1dm³; so this is 0.25dm³

P1 = 760torr

760torr = 1atm

V2 = 220cm³ ; 0.22dm³

Unknown:

New pressure = ?

Solution:

To solve this problem, we apply Boyle's law and we use the expression below:

P1 V1 = P2V2

The unknown is P2;

1 x 0.25 = P2 x 0.22

P2 = 1.14atm