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When 11 g H2(g) and 37.25 g CO(g) are combined, how many grams of methyl alcohol are produced?

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Hydrogen react with with carbon monoxide(Carbon (ii) oxide) to form methyl alcohol
CO + 2H2 ----> CH3OH
step one calculate the number of moles of H2

= 11g/2.0 g/mol (molar mass of H2 moles = 5.5moles
calculate the moles CO = 37.25grams/28 =1.330moles
The reacting ratio of of H2 to CH3OH 2:1
1.330 x 2/1+2.661 moles of H2 but there is more H2 present than that of co
therefore the grams of CH3OH is threfore =1.330 x32(molar mass of CH3OH) =42.65grams
User Dan Esparza
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