105k views
1 vote
Prove alebracically that 0.5 recurring is 5/9

1 Answer

6 votes
Let's first assign X the value of the repeating decimal. So X = 0.55555555...... Let's multiply both sides by 10 10X = 5.55555555....... Now let's subtract the 1st equality from the 2nd. 10X = 5.55555555..... - (X = 0.55555555.....) = 9X = 5 And finally, divide both sides by 9. X = 5/9 You can use the above technique for ANY repeating decimal by multiplying by 10^n power where n is the number of digits in the repeating cycle. For instance, 1/7 = 0.142857142857142857142857142857142857.... So the repeating portion is 142857 which is 6 digits long. So you'd multiply by 10^6 or 1000000.
User Lampyridae
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories