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Can someone help me with this question?!

Can someone help me with this question?!-example-1
User RThomas
by
3.8k points

2 Answers

10 votes

Answer:

i think c

Step-by-step explanation:

User Alex Yeung
by
4.4k points
10 votes

Answer:

Average atomic mass = 32 amu

Step-by-step explanation:

Given data:

Abundance of X-30.00 amu = 30%

Abundance of X-32.00 amu = 50%

Abundance of X-35.00 amu = 20%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass = (30×30)+(50×32)+(20×35) /100

Average atomic mass = 900 + 1600 +700 / 100

Average atomic mass = 3200 / 100

Average atomic mass = 32 amu.

User Tom Studee
by
4.3k points