Answer:
0.43 M
Step-by-step explanation:
The equation that should be used in this case would be:
pOH = pKb + log([A+]/[Base])
pKb = -log (4.6*10^-4) = 3.34
pOH = 14-10.2 = 3.8
[Base] = 0.15
3.8 = 3.34 + log x/0.15
0.46=log x/0.15
10^(0.46) = x/.15
x = 10^(0.46) * 0.15 = 0.43 M