Which equation is the inverse of y = 16x2 + 1?

Question

asked Mar 21, 2019 162k views

2 Answers

TomRavn · Answer 1 · 2019-03-26T11:24:59+0000

Answer:

y=(√(x-1) )/(4)

Explanation:

The given equation is

y=16x^2+1

For this function to have an inverse, we must restrict the domain, say
$x\ge0$

We interchange x and y to get,

x=16y^2+1

We now make y the subject to get;

x-1=16y^2

We divide through by 16 to get;

(x-1)/(16)=y^2

We now take the square root of both sides to get;

$\pm \sqrt{(x-1)/(16)}=y$

$y=\pm (√(x-1) )/(4)$

Since
$x\ge 0$ , the inverse function is

y=(√(x-1) )/(4)