Question

Which equation is the inverse of y = 16x2 + 1?

Answer 1

`y=((+/-)√(x-1) )/(4)` (D)

Explanation:

Edge 2020

Have a nice day :) <3

Answer 2

`y=(√(x-1) )/(4)`

Explanation:

The given equation is

`y=16x^2+1`

For this function to have an inverse, we must restrict the domain, say
`x\ge0`

We interchange x and y to get,

`x=16y^2+1`

We now make y the subject to get;

`x-1=16y^2`

`x-1=16y^2`

We divide through by 16 to get;

`(x-1)/(16)=y^2`

We now take the square root of both sides to get;

`\pm \sqrt{(x-1)/(16)}=y`

`y=\pm (√(x-1) )/(4)`

Since
`x\ge 0`, the inverse function is

`y=(√(x-1) )/(4)`