Question

In these reactions involving iodine (1), determine whether iodine is oxidized or reduced.

lodine (1) and hydrogen sulfide (H2S) combine to form hydrogen iodide and sulfur (Sa).
812 + 8H2S → 16HI + Sg lodine is
Iodine (12) and aluminum (AI) combine to form aluminum iodide (All)
312 + 2A1 - 2Allg
lodine is
lodine pentoxide (1205) and carbon monoxide (CO) combine to form iodine (la) and carbon dio
(CO2).
1205 + 500 12 + 5CO2 lodine is

Answer 1

The answer is 975S because u add all ofthem

Answer 2

1. Iodine is reduced

2. Iodine is reduced

3. Iodine is oxidized

Step-by-step explanation:

1. Oxidation number goes from 0 to -16

(oxidation number decreases = reduction)

2. Oxidation number goes from 0 to -6

(oxidation number decreases = reduction)

3. Oxidation number goes from +2 to 0.

(oxidation number increases; the atom loses electrons = oxidation)