Question

An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? You may use a trigonometry table

Answer 1

The height difference is found by

`\delta H=400sin(5 \°)=34.86m`
Then the change in potential energy is

`E=mgh=(80.0kg)(9.8 (kgm)/(s^2))(34.86)= 27332J`