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An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? You
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An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? You may use a trigonometry table

User Mhenrixon
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The height difference is found by

\delta H=400sin(5 \°)=34.86m
Then the change in potential energy is

E=mgh=(80.0kg)(9.8 (kgm)/(s^2))(34.86)= 27332J
User Eltonkamami
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