In algebra, the rational root theorem states a constraint on rational solutions of a polynomial equation

with integer coefficients. Solutions of the equation are roots of the polynomial on the left side of the equation.
If
and
are nonzero, then each rational solution x, when written as a fraction
in lowest terms satisfies
- p is an integer factor of the constant term
- q is an integer factor of the leading coefficient

For the polynomial
,
Find factors of these coefficients:
- factors of
are

- factors of
are

Therefore, possible roots are

Check all that apply:



Then

Answer: there are three possible factors

The last one can be rewritten as 3x-5, then
