2x= 3y-1
6x-9y= -3
So we can solve in 2 ways.
1- Substitution
2- Summate 2 equations
The 1st solution:
Choose x or y's congruent in one of the equation and find with residual equation.
2x= 3y-1
6x is three times of 2x so 6x= 3(3y-1)
6x= 9y-3
6x-9y=-3
9y-3-9y= -3
0=0
Solution set = (R)
2nd solution;
2x-3y=-1
6x-9y= -3
Multiple the first equation with (-3).
-6x+9y=3
6x-9y=-3
0=0
Solution set= (R)
Hope it helps!
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