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How many ways are there to pick a selection of coins from $1 worth of identical pennies, $1 worth of identical nickels, and $1 worth of identical dimes if (a) you select a total of 9 coins? (b) you select a total of 16 coins?

User ATom
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Final answer:

There are 53,769,225 ways to select 9 coins and 56,834,632,664 ways to select 16 coins from $1 worth of identical pennies, nickels, and dimes.

Step-by-step explanation:

To determine the number of ways to pick a selection of coins, we can use the concept of combinations. Since there are 100 pennies, 100 nickels, and 100 dimes, the total number of coins is 100 + 100 + 100 = 300. (a) If you select a total of 9 coins, you can choose different combinations of coins. To find the number of combinations, we use the formula C(n, r) = n! / (r!(n-r)!), where n is the total number of coins and r is the number of coins in the selection. In this case, n = 300 and r = 9. Substituting these values, we find C(300, 9) = 53,769,225 ways to select 9 coins. (b) If you select a total of 16 coins, you can similarly use the combination formula. Substituting n = 300 and r = 16, we find C(300, 16) = 56,834,632,664 ways to select 16 coins.

User Uan
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what? I do not understand the question
User Theeomm
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