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What value of y satisfies the equation 3y7+17=37 ?

User Sergnsk
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2 Answers

4 votes

\bf 3y^7+17=37\implies 3y^7=20\implies y^7=\cfrac{20}{3}\implies y=\sqrt[7]{\cfrac{20}{3}}
User Soumen Mukherjee
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2 votes
3y^7+17=37
3y^7=20
y^7=20/3
y=(20/3)^1/7
User Saada
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