199k views
5 votes
Lesson 10: Congruent Triangles ._.

Lesson 10: Congruent Triangles ._.-example-1
Lesson 10: Congruent Triangles ._.-example-1
Lesson 10: Congruent Triangles ._.-example-2

2 Answers

6 votes
#1 is A
#2 IS c
#3 is B
User Access Denied
by
8.2k points
4 votes

Answer:

Explanation:

The congruence
MN \cong PR is false, because they are not corresponding sides.

The corresponding sides are:


MN \cong PQ\\NO \cong QR\\MO \cong PR

On the other hand, if
\triangle ABC \cong \triangle PQR, then
\angle Q \cong \angle B.

We know that
m\angle Q=8v-6 and
m \angle B=3v+4, but they are equal, so


8v-6=3v+4\\8v-3v=6+4\\5v=10\\v=2

Then,


m\angle Q=8v-6=8(2)-6=16-6=10\\m \angle B=3v+4=3(2)+4=6+4=10

Therefore, those angles are equal to 10°.

In the second image, the given triangles have the following congruence:


\angle DAB \cong \angle CAB\\\angle DBA \cong \angle CBA

Also, they have side AB in common.

Therefore,
\triangle ABC \cong \triangle ABD, by ASA.

User Saera
by
8.4k points