199k views
5 votes
Lesson 10: Congruent Triangles ._.

Lesson 10: Congruent Triangles ._.-example-1
Lesson 10: Congruent Triangles ._.-example-1
Lesson 10: Congruent Triangles ._.-example-2

2 Answers

6 votes
#1 is A
#2 IS c
#3 is B
User Access Denied
by
8.2k points
4 votes

Answer:

Explanation:

The congruence
MN \cong PR is false, because they are not corresponding sides.

The corresponding sides are:


MN \cong PQ\\NO \cong QR\\MO \cong PR

On the other hand, if
\triangle ABC \cong \triangle PQR, then
\angle Q \cong \angle B.

We know that
m\angle Q=8v-6 and
m \angle B=3v+4, but they are equal, so


8v-6=3v+4\\8v-3v=6+4\\5v=10\\v=2

Then,


m\angle Q=8v-6=8(2)-6=16-6=10\\m \angle B=3v+4=3(2)+4=6+4=10

Therefore, those angles are equal to 10°.

In the second image, the given triangles have the following congruence:


\angle DAB \cong \angle CAB\\\angle DBA \cong \angle CBA

Also, they have side AB in common.

Therefore,
\triangle ABC \cong \triangle ABD, by ASA.

User Saera
by
8.4k points

No related questions found