Question

You can spend at most $60 on beads. A bag containing red beads costs $2 per bag. A bag containing blue beads costs $3 per bag. You need more bags of blue beads than bags of red beads. Write a system of linear equations that represents the situation.

Answer 1

`2r+3b\leq 60`

Explanation:

Let the number of blue beads bag be represented by = b

Let the number of red beads bags be represented by = r

A bag containing red beads costs $2 per bag. So, total price = 2r

A bag containing blue beads costs $3 per bag. So, total price = 3b

Now its given , you can spend at most $60 on beads so equation becomes:

`2r+3b\leq 60`

Answer 2

For this case, the first thing we must do is define variables.
We have then:
x: number of blue beads
y: number of red beads
We now write the inequations system:

`3x + 2y \leq 60 x\ \textgreater \ y`
Answer:
a system of linear inequations that represents the situation is:

`3x + 2y \leq 60 x\ \textgreater \ y`