In the Ridgeland Park youth athletics program, 60% of athletes play baseball and 24% of athletes play baseball and basketball. What percentage of athletes who play baseball also…

Question

asked Sep 3, 2019 137k views

2 Answers

Truman · Answer 1 · 2019-09-08T20:22:50+0000

Answer: 40%

Explanation:

Let A be the event that the athlete play baseball and B be the event that the athlete play basketball.

Given: The probability of athletes play baseball =
P(A)=0.60

The probability of athletes play baseball and basketball =
$P(B\cap A) = 0.24$

Then the probability that the athletes who play baseball also play basketball is given by :-

$P(B|A)=(P(B\cap A))/(P(A))\\\\\Rightarrow\ P(B|A)=(0.24)/(0.60)=0.4$

In percent ,
$0.4*100=40\%$

Hence, 40% of athletes who play baseball also play basketball.