Answer: 40%
Explanation:
Let A be the event that the athlete play baseball and B be the event that the athlete play basketball.
Given: The probability of athletes play baseball =
![P(A)=0.60](https://img.qammunity.org/2019/formulas/mathematics/high-school/63i7waeqf17ohcdaq1naq1yvipnikutfvv.png)
The probability of athletes play baseball and basketball =
![P(B\cap A) = 0.24](https://img.qammunity.org/2019/formulas/mathematics/high-school/om5wgsd88smggb1hf05pzawzdq2qxr4w38.png)
Then the probability that the athletes who play baseball also play basketball is given by :-
![P(B|A)=(P(B\cap A))/(P(A))\\\\\Rightarrow\ P(B|A)=(0.24)/(0.60)=0.4](https://img.qammunity.org/2019/formulas/mathematics/high-school/5n1qc3jsh8extay4qlr5vsotjmxnzzdqwz.png)
In percent ,
![0.4*100=40\%](https://img.qammunity.org/2019/formulas/mathematics/high-school/56njhujctt8va1k1sq8rirxmet6lig5our.png)
Hence, 40% of athletes who play baseball also play basketball.