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What volume of gold would be equal in mass to a piece of copper with a volume of 101 ml? the density of gold is 19.3 g/ml; the density of copper is 8.96 g/ml?

2 Answers

3 votes

Answer:

We need 46,88 ml of gold to have the same mass as 101 ml of copper

Step-by-step explanation:

First we have to calculate the mass of the piece of copper, remember that ml is a measure for volume, so we just have to solve the formula of density for mass:

Density=mass/volume

Mass=volume*density

And we instert the data that we knwo:

Mass=101*8.96

Mass= 904,96 grams

SO know that we now the mass of the copper piece, we can solve for volume in the formula of density to get how many mililiters of gold we need to have 904,96 grams:

Density=mass/volume

Volume=Mass/density

Volume= 904,96/19,3

Volume=46,88 mililiters

User Elwhis
by
7.2k points
4 votes
Answer is: volume of gold equal in mass to a piece of copper is 46,89 ml.
d(Cu) = 8,96 g/ml.
V(Cu) = 101 ml.
d(Au) = 19,3 g/mol.
V(Au) = ?.
m(Cu) = d(Cu) · V(Cu)
m(Cu) = 8,96 g/ml · 101 ml
m(Cu) = 905 g.
m(Au) = m(Cu) = 905 g.
V(Au) = m(Au) ÷ d(Au)
V(Au) = 905 g ÷ 19,3 g/ml.
V(Au) = 46,89 ml.

User Cylondude
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6.6k points