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½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole 21.0 kcal/mole + C(s) + 2S(s) → CS2(l) The temperature of the surroundings will: increase or decrease
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½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole 21.0 kcal/mole + C(s) + 2S(s) → CS2(l) The temperature of the surroundings will: increase or decrease

User Eboni
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Are we supposed to graph or solve
User Matthijs Brouns
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Answer:

½H2(g) + ½I2(g) → HI(g), ΔH = +6.2

This reaction has an positive entalpy, meaning heat flows from the surroundings into the system, thus decreasing surrounding temperature.

User Cheloute
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