Question

For the reaction of hydrogen with iodine

H2(g) + I2(g) rightarrow 2HI(g)
relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide.

Answer 1

`r_(H_2) = (-1)/(2) r_(HI)`

Step-by-step explanation:

Hello!

In this case, considering the given chemical reaction:

`H_2(g) + I_2(g) \rightarrow 2HI(g)`

Thus, by applying the law of rate proportions, we can write:

`(1)/(-1) r_(H_2) = (1)/(-1)r_(i_2) = (1)/(2) r_(HI)`

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

`r_(H_2) = (-1)/(2) r_(HI)`

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