Question

How much heat is needed to raise the temperature of 7g of water by 19oC?

Answer 1

Answer: The heat required is 556.738 Joules.

Step-by-step explanation:

To calculate the heat required, we use the equation:

`Q= m* c* \Delta T`

where,

Q = heat absorbed = ? Joules

m = mass of water = 7g

c = heat capacity of water = 4.186 J/g ° C

`\Delta T=\text{Change in temperature}=19^oC`

Putting values in above equation, we get:

`Q=7g* 4.186J/g^oC* 19^oC`

Q = 556.738 J

Hence, the heat required by water is 556.738 Joules.

Answer 2

Data:

m = 7 g

ΔT = 19 °C

Cs of water = 1 cal / g °C

Formula Q = m * Cs * ΔT

Solution:

Q = (7 g) * (1 cal / g °C) * ( 19°C) = 133 cal