94 * 1.602 * 10^-19 =150.588 * 10^-19 C F = kQ(-e)/r^2 we know r = 9.75 angtroms or 9.75 An electric point charge of Q1 = 8.31 nC is placed at the origin of the real axis. Another point charge of Q2 = 2.07 nC is placed at a position of p = 3.06 m on the real axis.Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?