Question

What is the equation of the line that passes through the points (-2, 2) and (0, 5)?

Answer 1

Greetings!

We can use these points to find the slope of a line, using the slope formula:
`m= (y_(2)-y_(1))/(x_(2)-x_(1))`

Input the points:

`m= ((5)-(2))/((0)-(-2))`

Combine like terms:

`m= (3)/(2)`

The Slope is Equal to:

`\boxed{(3)/(2)}`

To find the y-intercept of the line, we use the slope and the points. First, arrange the equation is slope y-intercept form:

`y=mx+b`

Input the slope and one of the points:

`(5)=(3)/(2)(0)+b`

Combine like terms:

`(5)=b`

The y-intercept is Equal to:

`\boxed{5}`

The Equation of the Line Is:

`\boxed{y=(3)/(2)x+5}`

I hope this helped!
-Benjamin