Answer:
R = 50 Ω / 3 = 16.7 (or 1/R = 1 / R1 + 1 / R2 + 1 / R3)
i1 = 24.0 = 50 = .48 amps thru each branch
I = i1 + i2 + i3 = 3 * .48 = 1.44 total current
Note (24.0 / 16.7 = 1.44 amps)
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