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Suppose the path of a baseball follows the path graphed by the quadratic function ƒ(d) = –0.6d2 + 5.4d + 0.8 where d is the horizontal distance the ball traveled in yards, and ƒ(d) is the height, in yards, of the ball at d horizontal yards. Identify the domain and range that matches this situation.

User Drprofee
by
6.6k points

2 Answers

4 votes

Answer:


Domain is all real numbers


Range is



y\le 12.95



Explanation:


The given function is



f(d)=-0.6d^2+5.4d+0.8


This is a maximum quadratic function therefore the domain is all real numbers.


Let us complete the square to find the vertex.




f(d)=-0.6(d^2-9d)+0.8




f(d)=-0.6(d^2+9d)+-0.6((9)/(2))^2- -0.6((9)/(2))^2+ 0.8





f(d)=-0.6(d-(9)/(2))^2+(243)/(20)+ 0.8






f(d)=-0.6(d-(9)/(2))^2+(259)/(20)






Therefore the range is





y\le (259)/(20)




y\le 12.95


See graph




Suppose the path of a baseball follows the path graphed by the quadratic function-example-1
User SeToY
by
6.9k points
4 votes

Answer:

Domain:


[0,9.146]

Range:


[0,12.95]

Explanation:

we are given

a baseball follows the path graphed by the quadratic function


f(d)=-0.6d^2+5.4d+0.8

where

d is the horizontal distance the ball traveled in yards

ƒ(d) is the height, in yards, of the ball at d horizontal yards

Domain:

we know that domain is all possible values of x for which any function is defined

So, for finding domain , we will take smallest x-value to largest x-value

so, we can set f(d)=0 and find zeros


-0.6d^2+5.4d+0.8=0

we can use quadratic formula


d=(-b\pm √(b^2-4ac))/(2a)


d=(-54\pm √(54^2-4\left(-6\right)8))/(2\left(-6\right))


d=-(√(777)-27)/(6),\:d=(27+√(777))/(6)


d=-0.14579,d=9.146

we know that d is a horizontal distance

and distance can never be negative

so, domain will be


[0,9.146]

Range:

Since, this is quadratic equation

so, it is also equation of parabola

so, firstly we will find vertex of parabola

Suppose, we have


ax^2+bx+c=0

Vertex is


x=(-b)/(2a)

so, we can compare

a=-0.6

b=5.4

c=0.8

now, we can find vertex


x=(-5.4)/(2* -0.6)


d=4.5

now, we can find y-value


f(4.5)=-0.6(4.5)^2+5.4(4.5)+0.8


f(4.5)=12.95

we can see

that leading coefficient is -0.6

which is negative

so, parabola opens downward

so, range will be


[0,12.95]

User Stefan Schultze
by
6.1k points
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