Question

Please help!!!
Find the correlation coefficient of the data. Round to the nearest hundredth.

Answer 1

The correlation coefficient is 0.0002273427

Explanation:

Given the data of heart rate and we have to find the correlation coefficient which can be calculated as

`r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^(2)-(\sum x)^(2) ] [n\sum y^(2)-(\sum y)^(2) ] }} }`

=
`=(12(7949)-68(1341))/(√([12(430)-4624][12(152729)-1798281]) )`

=
`(4200)/((536)(34467))`

= 0.0002273427

Answer 2

r ≈ 0.98

Explanation:

The correlation coefficient is easily calculated by almost any scientific or graphing calculator, or by a spreadsheet. It is mainly a matter of data entry and invoking the appropriate function. Here, the correlation coefficient is computed as about 0.97716, or 0.98 when rounded to the nearest hundredth.