Question

There are 8 blue marbles and 7 red marbles in a bag. Julie pulls two marbles at random from the bag first. What is the probability that she first pulls a blue marble and then a red marble?

Answer 1

either a ratio 8;7. or a percentage of 53% for picking the blue marble first i think and a 50/50 chance if you keep that blue marble out.

Explanation:

Answer 2

Answer:
`(4)/(15)`

Explanation:

Given: Number of blue marbles = 8

Number of red marbles = 7

Total number of marbles = 8+7=15

Now, the probability that she first pulls a blue marble is given by :-

`P(B)=\frac{\text{blue marbles}}{\text{Total marbles}}\\\\=(8)/(15)`

Now, total marbles left in bag = 15-1=14

Now, the probability that she second pulls a red marble is given by :-

`P(B)=\frac{\text{red marbles}}{\text{Total marbles left}}\\\\=(7)/(14)=(1)/(2)`

Thus, the probability that she first pulls a blue marble and then a red marble is given by :-

`P(B)*P(R)=(8)/(15)*(1)/(2)=(4)/(15)`